See image below
The solve( function was not able to find the intersection point because
it lies outside the graph range. The window dimensions are too narrow to
contain that point. I suggest you restrict the graph to the quadrant
where you suspect the solution to be (example first quadrant if
appropriate) : take Xmin=0, Ymin =0 and choose Xmax and Ymax large
enough to enclose the intersection point.
In your particular case there is an intersection point at (11.60, 5/28). You can also solve the equation 5/28= (0.85)^(X-1) simply by using the rules for logarithms ln(5/28)= (X-1) ln(0.85). So X-1=(5/28)/ln(0.85)=-1.098773. which gives X=1-1.09877=-0.098773
10,541 views
Usually answered in minutes!
×