Dewalt dc 742 torque adjuster stuck - Dewalt DC925 Cordless Drill

Torque converter clutch - stuck on.

hi
like most clutches on hummer unit after the assembly has been done you will a way to tighten the spring clutch look for adjustment to make the spring looser and tighten

I'm answering without knowing which model you have but, there are some Dewalt drills that will go into hammer and/or drill mode only if the speed selector is in 2nd gear. The torque settings are accessable only in driver mode. Short of that you may have broken parts in the transmission that can only be repaired by replacing the transmission.

p0742 is torque convertor curcuit stuck on. good-day!

Yes, that would be to adjust the screw driving torque etc.

The torque settings are not tightly controlled so they are not all that repeatable from drill to drill. They also vary somewhat with the speed of the drill and the condition of the battery. And they aren't linear (a setting of 10 is not twice the 5 setting) Simplest thing to do for a rough idea is to use your hand to hold the chuck still to feel how much torque you have at each setting. (start low and grip it tight!) If you want a specific torque setting, say 10 ft-lbs, then put a stout screw in a scrap of wood, hang a 10 lb weight on it 12 inches from the screw and adjust until it just starts to slip.

Here is DeWalt's marketing thing on the subject.

http://www.dewalt.com/us/cordless/powerrating/

Unit Watts out (UWO) is their rating for the (presumably sustainable)maximum power output at the chuck of the drill. You can read about it..their explanation is basically technically correct.

Yes, max torque is related. The maximum power in a permanent magnet DCmotor system occurs at half the maximum speed when the system is loadedwith half the maximum torque.

1hp = 746 watts, DeWalt's DC900 36V drill is claimed to be 750 watts,close enough so let's call it 1 HP ok? Their max RPM is 400. So 200 RPMis the half-way point.

1HP = 200RPM*Tmax(in-lbs)/(24*5252)

Tmax = approx 630 in-lbs

The equation I used is known equation for relating power (HP) to RPMand torque (in ft-lbs..I added in the factor of 1/12 to account for thein-lbs to ft-lbs conversion).

By the way DeWalt make some bold claims about other manufacterers' drills.

For example they claim the 18V Lok Tor by Milwaukee puts out 390 UWOcompared to their DC988 model listed as 420 UWO. Yet I have readinformation from Milwaukee's own independent tests that claim the LokTor drills faster 2 9/16" self-feeds AND more self-feeds per batterythan that very DeWalt model.

This was posted on Milwaukee's Tool Talk forum (when it existed). Ibelieve the Milwaukee official said that DeWalt averaged 7.2 secondsper hole while the Milwaukee averaged 6.4 seconds per hole. I make beoff slightly but I do remember it was around a 1 second difference.Plus the Milwaukee apparently drilled 28 holes per batt where dewaltwas 25.

38Nm Max Torque

with 22 adjustable settings

Source of information: https://www.tools4trade.com/shop_productdetail.aspx?pid=142022

Hope this helps,
david

If my solution helps please rate accordingly.

remove the spindle housing ,turn the collar spindil, if i d'ont turn replace 629828-00 spindle & clutch assy.
if i turne check the transmission 613237-00

in drill mode slips will not tork