-
Expert
233 Answers
- Posted on Mar 02, 2011
Re: How do you solve anti-logs..?
If Log y = x, then y = e^x. That is e^(log x) = y. So if you want the anti-log of 12, you just punch in e^12. That's assuming we're using the natural logarithm. If it were base 10 it would be 10^12, if it's base 2, it would be 2^12, etc.
×